00 / 1500000 = 5.1866 I rounded 5.1866 to 5.2 astronomical units. I then used Kepler’s third law to figure out the orbital period of Jupiter. P = R^3/2P = (5.2)^3/2P = 11.8578 years Jupiter is 5.2 astronomical units away from the sun and its orbital period is 11.8578 years. Kepler’s laws were important for many reasons. They allowed astronomers to track and predict the motions of the planets more accurately. They also showed that not only objects on earth follow laws, but also objects in the universe do to. This showed scientists that it was possible to study and understand the universe. (Fleisher, 20)After Kepler passed away Sir Issac Newton an astronomer / mathematician / physicist, improved upon much of Kepler’s work and also made some of his own discoveries. All of Kepler’s laws can also be used dealing with satellites because they are in orbit just like the planets. Much of the work done in modern astronomy is still based on Kepler’s three laws of planetary motion. He was very advanced for his time, and if he had not made such great discoveries the human race would have been far behind in the exploration of outer space....
