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Conservation of Momentum

.00436 Kg m/s2.) Inelastic collision: Total momentum before = Total momentum after mv + mv = (m + m ) v (.3105kg x .016 m/s) + 0 = (.3105 kg + .3000 kg) x .008 m/s.0050 Kg m/s =.0049 Kg m/sConclusion: Through experiments with strobe photos involving elastic and inelastic collisions, I was able to show that momentum is contained within a closed system. My efficiency for the elastic collision was 3.54% and my efficiency for the inelastic collision was 1.01 %. Less than 10 % of the momentum was lost in either collision indicating a good experiment. The lost momentum can be attributed to the transfer from mechanical energy to thermal energy.Sources of Error:1.) The distances measured in the two strobe photos were estimated.2.) The measurement of time was an average.% error = difference x 100 sum of all1.) % error = .00032 x 100 = 3.54 % error .00904 2.) % error = .0001 x 100 = 1.01 % error .0099...

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