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terminal velocity

o be started and stopped on a fixed point.A group of ball bearings were massed with an electric balance and an average of the ball bearings were taken. These ball bearings were massed so that an average mass could be calculated for each size of the ball bearings, by dividing the total mass of the ball bearings by the number of ball bearings.The ball bearing was placed on the fluids surface and let to fall through the fluid.A stop clock was started when the ball bearing reached the first elastic band and stopped when it reached the second elastic band.The results were repeated three times for an accurate average time and any “strange results” were repeated to improve accuracy.The results are shown in a table on the next page.DiagramResultsAverage mass resultsBallNumber of BallsMass (g) (2dp)Average mass of one ball (g) (2dp)A601.800.03B303.370.11C5022.070.44D5044.200.88E3061.542.05Terminal Velocity ResultsAverage mass (g) (2dp)Distance Fallen (cm) (1dp)Time of Fall (s) (1dp)Terminal Velocity (cm/s) (1dp)Trial 1Trial 2Trial 3Average0.0360.050.448.648.949.31.20.1160.022.920.620.821.42.80.4460.010.310.210.310.35.80.8860.07.17.06.56.98.72.05604.84.64.74.712.8GraphSee graph paper.ConclusionI have found that my prediction is correct with the fact that as the mass of the ball bearing increases so does the weight of the ball bearing, which requires more friction to balance the ball bearing’s weight thus making the terminal velocity increase.Therefore the velocity of the ball bearing would increase which is a greater force than the friction required to balance the ball bearing, which accelerates the ball bearing. As the ball bearing accelerates the friction acting against the falling ball bearing increases which in turn balances out the forces applied to the ball bearing thus reaching the terminal velocity of the ball bearing.My mathematical prediction, which I have found to be incorrect because the terminal velocity can change ...

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