aph and table of results, I have noticed several things. When the length changes so does the resistance. As you can see from the graph, as the length of the putty increases, the resistance increases as well. My graph is a straight line, which passes through the origin; therefore the resistance is directly proportional to the length of the putty. This means that if the length of the putty doubles so does the resistance.For example, reading from my graph using the line of best fit. When the length of the putty is 2cm the resistance is 3.50Ω, so if the length of the putty is double 2cm, which is 4cm, the resistance is 7.00Ω, this is double the resistance for a piece of putty, which is 2cm long in length.(See graph)Therefore my prediction was correct.I based my prediction on the theory that longer wires will cause an increase in resistance, because the electrons have to travel past more atoms and collisions than they do in shorter wires, in this case the putty. This means that it will take a longer time for electrons to past through a long piece of putty than a short piece of putty, and that is why there will be a big value in resistance. (The longer the putty the bigger the resistance). Also, long thin putty has more resistance than a short thick one of the same material.I also based my theory on Ohms Law. Ohm’s law states that for a wire under constant physical conditions, the current is proportional to the voltage. This is also equivalent to stating that resistance is constant. If the current through a conductor is I when the voltage across it is V, its resistance R is defined by R= V / I.Resistance (R) is measured in Ohms (Ω).The ohm is the resistance of a conductor in which the current is 1 ampere when a voltage of 1 volt is applied across it. Metals and some alloys give I-V graphs, which are a straight line through the origin, so long as their resistance is constant. Current (I) is directly proportional to Volt...
