tin = 79.5 gTinitial-slug = 155 CTintial-h20 = 36.5 CTfinal = 39 CC?? = (mcup CAl + mrod CAl + mh20 Ch20) (Tfinal – Tinitial-h20) / (Tinitial-slug – Tfinal) m??Ctin = (50 903 + 11 903 + 200 4180)(39 – 36.5) / (155 – 39) (79.5)Ctin = 241.6Analysis & Conclusions:In this examination of physical reactions, observing, presenting, predicting, identifying, and recognizing were the essential elements in this laboratory experimentation. By correctly performing the correct procedures, it was relevant that many repercussions occurred. The great difference between the two calculations for the heat capacity of the calorimeter is evidence of an experimental problem. This problem probably lies in the fact that the hot water placed in the calorimeter was not de-ionized. This would mean that the specific heat of water, which was regular tap water, might also yield an inconsistent amount of additives per sample. This would also change the calculated heat capacity. The specific heat that was calculated for the aluminum was consistent. Both answers were within a tenth of a Joule per gram degree Celsius. The fact that an experiment that did not use the specific heat of water so any times, though wrong, and that was consistent, leads me to believe that the water was the source of error. ...
