of hypothesis test was chosen is because the population in normally distributed, which has to be true for this to work. In this test it is necessary to produce a test statistic. The test statistic for this test is (d-do)/(sd/(n^(1/2))). Where d is di/n and sd is (((di^2)-((di)^2/n))/(n-1).On the histogram that I have printed up for this test the difference between the mean is on the horizontal axis while the percentage is on the vertical axis. By the graph you can tell that approximately 40% of the mice without supplements had a slightly greater endurance than the mice with the supplements. About 55% of the mice with the supplement had a slightly greater endurance than the mice without the supplement. Also about 10% of the mice with the supplement had much higher endurance than the mice without the supplement. For this the decision is to fail to reject the null hypothesis because the p-value is greater than alpha (.05). The conclusion is that at alpha equal to .05(a=.05) there is insufficient evidence to conclude that the mean difference between the two types of mice (ones with the supplement and ones without the supplement) is equal to zero....
