means that the resistance is equal to 2 ohms.Given a 10 V battery, by V = I R (ohms law) the total current in the circuit is: I = V / R = 10 / 2 = 5 A.The individual currents can also be found using I = V / R. The voltage across each resistor is 10 V, so:I1 = 10 / 8 = 1.25 AI2 = 10 / 8 = 1.25 AI3=10 / 4 = 2.5 A In parallel circuits, the voltage is the same. V1 = V2 = V3 =? = VnFrom the Reference: http://buphy.bu.edu/py106/notes/Circuits.htmlIII.DIAGRAM/MATERIALS? battery? voltmeter? ammeter? 3 resistance boxes? wiresSETUP 1 SERIESSETUP 2 PARALLEL SETUP 3 PARALLEL AND SERIESIV.PROCEDUREThe power source, wire, and the 3 resistance boxes are arranged in a way that it follows the set-up above. In all the set-ups the current is determined through the ammeter, the voltage through the ammeter, the 1st 3 resistances should be set at 10,20,30 ohms. Record the current, voltage, and the resistances in their respective tables. Calculate the missing values (refer to the formula below V) and compute for the percentage difference. V.DATA Table 1 ? Resistors in SeriesResistance R (Ohms)Voltage V ( Volts ) Current I (Amp)Computed R V/I (Ohms)R1 10 ?V1 0.2I1 0.02V1/I1 10R2 20 ?V2 0.4I2 0.02V2/I2 20R3 30 ?V3 0.6I3 0.02V3/I3 30R4 65 ?V4 1.3I4 0.02V4/I4 65R4* 60 ?V4* 1.2 %R4 8%%V 8%R4*= R1 + R2 + R3 V4* = V1 + V2 + V3 R4 = V4/I4Table II Resistors in ParallelResistance R (Ohms)Voltage V (volts)Current I (amp)Computed RR1 10?V1 1.25 voltsI1 0.07V1/I1 17.9 ?R2 20?V2 1.25 voltsI2 0.04V2/I2 31.25?R3 30?V3 1.25 voltsI3 0.03V3/I3 41.67?R4 8.92?V4 1.25 voltsI4 0.14V4/I4 8.92?R4* 5.45 ?%R 48%I4* 0.14%I 0%R4* computed from 1/R1 + 1/R2 + 1/R3I4* = I1 + I2 + I3Table III Resistors in Parallel and SeriesResistance R (Ohms)Voltage V (volts)Current I (amp)Computed RR1 10?V1 1.1 voltsI1 0.08V1/I1 13.75 ?R2 20?V2 1.3 voltsI2 0.05V2/I2 26 ?R3 30?V3 1.3 voltsI3 0.04V3/I3 32.5 ?R4 ...