23?V4 2.4 voltsI4 0.08V4/I4 30 ?R4* 22?R* 2.4I4* 0.12%I 40%R4 = R1 + 1/ ((1/R2)+ (1/R3))V4*= V1 + V2 VI.SAMPLE COMPUTATIONSERIES:R4*= R1 + R2 + R3 = 10 + 20 + 30 = 60? V4* = V1 + V2 + V3 = 0.2 + 0.4 + 0.6 = 1.2 voltsPARALLEL R4* computed from 1/R1 + 1/R2 + 1/R3 R4* = 1/10 + 1/20 + 1/30 = 5.45 ? I4* = I1 + I2 + I3 = 0.07 + 0.04 + 0.03 amperesSERIES AND PARALLELR4 = R1 + 1/ ((1/R2)+ (1/R3))V4*= V1 + V2 R4 = 10 + 1/ ((1/20)+1/30)) = 23 ?V4*=1.1+1.3 = 2.4 voltsPercentage Difference%V= / 1.3-1.2 / = 8% /(65+60)/2/ %R= / 65-60 / = 8% /(1.3+1.2)/2/ VII.ANALYSIS Based on the data that we have gotten from the experiment, we have proven that the current in series is equal and the voltage in parallel circuits are the same. I have also noticed that adding resistors in series has increased its total resistance while connecting additional resistors in parallel has decreased the total resistance. This explains that the total resistance of the resistors in series is greater than the individual resistances while on the contrary; the total resistance of a parallel group is always less than the individual resistances. The percentage difference of the experiment is due to the malfunctioning of the materials while we were conducting the experiment. VIII.CONCLUSIONIn conclusion, I can say that connection is in series when electricity flows uniformly from one resistor to the next. In series, the current is equal and the total voltage is derived by adding their individual voltages. The total resistance of a series connection is also derived by adding their individual resistances. However, when the connection is parallel the total current is the result of the sum of the individual currents while the voltage is equal. The reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. The total resistance o...
