etting into the third octet.Make sure you verify the address class. Even though the Subnet Mask extends into the third octet, the address is Class "A." In this case, there are 16,382 Subnets each containing 1022 Hosts.Subnet ID has 14 spaces (11111111111110 = 16382)Host ID has 10 spaces (111111111 = 1022)We can verify the validity of an address simply by converting both the IP Address and the Subnet Mask into Binary, separating the IP address into Network ID, Subnet ID, and Host ID. If any of the IDs is either all 1’s or all 0’s then the address is not valid.01101101 0000 1111.10101010 = Not Valid All 0’s in the Subnet ID This address would not be valid. To make this address valid we would have to place a valid number in the Subnet ID part of the IP Address, or adjust the Subnet Mask to cover one more bit. 11111111.11110000. 00000000.00000000Switch this 0 to a 1.To determine the range of the IP address, separate the host id from the Network and Subnet IDs.IP Address 10110101.01101001.001 00000.00000001Subnet Mask 11111111.11111111.111 00000.00000000 Network/Subnet IDs Host IDWithout changing the Network / Subnet Ids, figure the smallest and largest host numbers available. (All 0’s with a 1 on the end = Smallest. All 1’s with an 0 on the end = Largest.) Then translate both complete addresses back to decimal. This is your range.10110101.01101001.001 00000.00000001 = 181.105.32.110110101.01101001.001 11111.11111110 = 181.105.63.254To verify if two addresses are on the same Subnet just translate the IP Addresses and the Subnet into Binary and verify that the Network IDs and Subnet IDs are the same on each IP address.181.105.112.17 = IP Address #110110101.01101001.011 10000.00010001181.105.120.129 = IP Address #210110101.01101001.011 11000.11000001255.255.224.0 = Subnet Mask 11111111.11111111.111 00000.00000000The Network IDs must be the same.The Host IDs will be different.Using these...
